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LOGARITHMS (Continued)

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LOGARITHMS (Continued)
Logarithms · Indices, Powers & Roots

LOGARITHMS (cont’d)

1. Relationship between Indices and Logarithms

A logarithm is simply another name for an exponent or power. The two concepts are directly related.

📌 Core idea: If you can write a number as a power of another number, you can also express it as a logarithm.

1000 = 103   →   log₁₀ 1000 = 3

Table: Numbers as powers of 10

NumberPower of 10Logarithm (base 10)
100010³log 1000 = 3
10010²log 100 = 2
1010¹log 10 = 1
110⁰log 1 = 0
0.110⁻¹log 0.1 = –1
0.0110⁻²log 0.01 = –2
0.00110⁻³log 0.001 = –3

General rule: If y = nx, then x = logn y. A logarithm answers: “To what power must the base be raised to get this number?”

Example with base 2: Since 32 = 25, then log₂ 32 = 5.

2. Converting Between Index and Logarithmic Forms

Any statement in index (exponential) form can be rewritten in logarithmic form – and vice versa.

▸ Index → Logarithmic

Index formLogarithmic form
2⁻³ = ⅛log₂(⅛) = –3
3⁶ = 729log₃ 729 = 6
4³ = 256log₄ 256 = 3

▸ Logarithmic → Index

Logarithmic formIndex (exponential) form
log₁₀(1/1000) = –310⁻³ = 1/1000
log₂ 64 = 62⁶ = 64
log₅(1/125) = –35⁻³ = 1/125

Example 1: Express in logarithmic form:
a) 2⁻³ = ⅛   →   log₂(⅛) = –3
b) 3⁶ = 729   →   log₃ 729 = 6
c) 4³ = 256   →   log₄ 256 = 3

Example 2: Express in index form:
a) log₁₀(1/1000) = –3   →   10⁻³ = 1/1000
b) log₂ 64 = 6   →   2⁶ = 64
c) log₅(1/125) = –3   →   5⁻³ = 1/125

📝 Evaluation

  1. Given that log₃ 81 = m, then 3m = 81. What is m?
  2. Find the value of log₂ 128.
  3. Fill in the blank box: log  ⬜  343 = 3
Show answers

1) 3⁴ = 81 → m = 4.   2) 2⁷ = 128 → log₂ 128 = 7.   3) 7³ = 343 → base = 7.


3. Calculating Powers and Roots Using Logarithm Tables

When using logarithm tables for powers and roots:

  • For powers: multiply the logarithm of the number by the power.
  • For roots: divide the logarithm of the number by the root index.
Then find the antilog of the result.

Example 1: 252.82

NumberLogOperation
251.3979× 2.82
Result3.9421antilog → 8750

✅ 252.82 ≈ 8750

Example 2: ⁶√35.81

NumberLogOperation
35.811.5540÷ 6
Result0.2590antilog → 1.816

✅ ⁶√35.81 ≈ 1.816

Example 3: √26.21

NumberLogOperation
26.211.4185÷ 2
Result0.7093antilog → 5.121

✅ √26.21 ≈ 5.121

Evaluation (powers & roots):
1) 3.53³   2) ⁴√400

4. Calculations Involving Multiplication, Division, Powers & Roots

When multiple operations appear, handle numerator and denominator separately using logs, then subtract.

Example A: (√94100 × 38.2) / (5.683 × 8.14)

StepValueLogOperation
1√941004.9736 ÷ 2 = 2.4868
238.21.5821+
Numerator4.0689
35.6830.7540 × 3 = 2.2620
48.140.9106+
Denominator3.1726
5Subtract4.0689 – 3.1726 = 0.8963antilog → 7.878

✅ Result ≈ 7.88 (3 s.f.)

Example B: ∛(19.63 × 12.28² × 74)

StepValueLogOperation
119.631.2930
212.28²1.0890 × 2 = 2.1780+
3741.8692+
Total5.3402÷ 3
4Result log1.7801antilog → 60.29

✅ ≈ 60.3 (3 s.f.)

Example C: ∛( (218 × 37.2) / 95.43 )

StepValueLogOperation
12182.3385
237.21.5705+
Numerator3.9090
395.431.9797– (subtract)
Difference1.9293÷ 3
4Final log0.6431antilog → 4.397

✅ ≈ 4.40 (3 s.f.)

Example D: ∛( (38.32 × 2.964) / (8.637 × 6.285) )²

StepValueLogOperation
138.321.5835
22.9640.4718+
Numerator2.0553
38.6370.9364
46.2850.7983+
Denominator1.7347
5Subtract2.0553 – 1.7347 = 0.3206× 2
6After square0.6412÷ 3
7Final log0.2137antilog → 1.636

✅ ≈ 1.636


5. Evaluation Exercises

Use logarithm tables (or calculator) to evaluate correct to 3 s.f. where needed:

  1. 3.53³
  2. ⁴√400
  3. ∛(1064 / 29.4)
  4. ( (403.9 × 5.78) / (70.62 × 2.931) )²

6. General Evaluation

  1. If log₅ 0.04 = m and 5m = 0.04, find m.
  2. Using logarithm tables, evaluate:
    a) (35.61)² × 5.62 / ∛143.5
    b) ∛(634.6² / 21.5)
Tip: For quick practice, rewrite each index statement in log form and vice versa. Master the table of powers of 10 — it builds intuition.

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